7n^2+3n-5=0

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Solution for 7n^2+3n-5=0 equation: 



7n^2+3n-5=0

a = 7; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·7·(-5)
Δ = 149
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{149}}{2*7}=\frac{-3-\sqrt{149}}{14}
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{149}}{2*7}=\frac{-3+\sqrt{149}}{14}
$

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